Show the given trigonometric equation — task. Maths CBSE Homework Assignments, Class 10.

Answer variants:

\frac{\sin θ + \sin θ \cos θ + \sin θ + \sin θ \cos θ}{1 - \cos^{2} θ}

\frac{2}{\sin θ}

\frac{\sin θ - \sin θ \cos θ + \sin θ + \sin θ \cos θ}{1 - \cos^{2} θ}

\frac{2 \sin θ}{1 - \cos^{2} θ}

\frac{2 \sin θ}{\sin^{2} θ}

\frac{\sin θ (1 - \cos θ) + \sin θ (1 + \cos θ)}{(1 + \cos θ) (1 - \cos θ)}

\frac{\sin θ (1 + \cos θ) + \sin θ (1 - \cos θ)}{(1 + \cos θ) (1 - \cos θ)}

Show that

\frac{\sin θ}{1 + \cos θ} + \frac{\sin θ}{1 - \cos θ}

\(=\)

2 cosec θ

Proof:

LHS \(=\)

\frac{\sin θ}{1 + \cos θ} + \frac{\sin θ}{1 - \cos θ}

\(=\)

2 cosec θ

\(=\) RHS

Did you find an error?

4. Show the given trigonometric equation