Product of difference and sum (common fractions) — task. Maths CBSE Homework Assignments, Class 7.

Do the multiplication

(\frac{1}{6} k - \frac{4}{13} l) \cdot (\frac{1}{6} k + \frac{4}{13} l)

Choose the correct answer:

$\frac{1}{36} k^{2} - \frac{16}{169} l^{2}$
$\frac{1}{36} k^{2} - 2 \cdot \frac{1}{6} k \cdot \frac{4}{13} l + \frac{16}{169} l^{2}$
$\frac{1}{36} k^{2} - \frac{8}{78} k l + \frac{16}{169} l^{2}$
$\frac{1}{36} k^{2} + \frac{8}{78} k l + \frac{16}{169} l^{2}$
$\frac{1}{36} k^{2} + 2 \cdot \frac{1}{6} k \cdot \frac{4}{13} l + \frac{16}{169} l^{2}$

Did you find an error?

2. Product of difference and sum (common fractions)